Question: The displacement of a particle at time t is given by $ \vec{x}=a\hat{i}+bt\hat{j}+\frac{c}{2}t^{2}\hat{k} $ where a, b and c are positive constants. Then the particle is
Options:
A) accelerated along $ \frac{18}{5} $ direction
B) decelerated along $ \frac{18}{5} $ direction
C) decelerated along $ \hat{j} $ direction
D) accelerated along $ \hat{j} $ direction
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Answer:
Correct Answer: A
BETA
